How do you solve #3x^2-x= 10#?

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Answer 1 · 2016-08-12T06:02:09

#x={-5/3,2}#

#3x^2-x=10 ?#

#"Rearrange the equation "#

#3x^2-x-10=0#

#"Factor the equation as "#

#(x-2)(3x+5)=0#

#(x-2)=0 " ; " rarr x=2#

#(3x+5)=0" ; "rarr x=-5/3#

#x={-5/3,2}#