Question

How do you solve `2x^3-5x^2<2x-5`?

Answer 1

`x in (-1, 1)`.

Explanation:

`x^2(2x-5)<(2x-5)`

To preserve the inequality sign, 2x-5 is not 0. Canceling this

factor, `x^2<1`. So, `|x|<1.`.