How do you simplify #sqrt 4times sqrt 4#?

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Answer 1 · 2016-08-12T22:43:13

#sqrt 4 xx sqrt 4 =4#
A Square and a square root are inverse operations and cancel each other out.

Each operation has an inverse. One does, the other undoes.

#+6 -6 =0#

#8 xx 3 div 3 = 8#

#sqrtx^2 = x#

In this case we have two possible methods

#sqrt 4 xx sqrt 4 = sqrt16 =4#

OR #(sqrt4)^2 # = 4