Question

What is the center of the circle `(x-1)^2 + (y+3)^2=16`?

Answer 1

The center is at `(1, -3)`.

Explanation:

When dealing with the form `(x - a)^2 + (y - b)^2 = r`, the center is at `(a, b)` and the radius is `sqrt(r)`.

Hopefully this helps!