What is the vertex form of $y= 2x^2 + 5x - 3$ ?

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Answer 1 · 2016-08-13T11:48:15

$"The form of equation is:"$

$y=2(x+5/4)^2-49/8$

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$y=ax^2+bx+c" Standard form"$

$y=a(x-h)^2+k" Vertex form"$

$P(h,k) "represents the coordinate of vertex"$

$y=2x^2+5x-3$

$a=2" ; "b=5" ; "c=-3)$

$h=-b/(2a)$

$h=-5/(2*2)=-5/4$

$k=2*(-5/4)^2+5*(-5/4)-3$

$k=2*25/16-25/4-3$

$k=50/16-25/4-3$

$k=(50-100-48)/16$

$k=-49/8=-6.13" Rounded the two decimal place"$

$"The form of equation is:"$

$y=2(x+5/4)^2-49/8$

What is the vertex form of y= 2x^2 + 5x - 3 y= 2x^2 + 5x - 3 ?