How do you solve 4x^2-8x+3<0? Precalculus Solving Rational Inequalities Polynomial Inequalities 1 Answer Alan P. Aug 13, 2016 color(green)(x in (1/2,3/2) Explanation: 4x^2-8x+3 < 0 can be factored as (2x-1)(2x-3) < 0 {: (2x-1 < 0,color(white)("XXX"),2x-3 < 0), ("if " x < 1/2,,"if " x < 3/2) :} (2x-1)(2x-3) will be less than zero if one but not both of the terms are less than zero. That is (2x-1)(2x-3) < 0 color(white)("XXXXXXXXXXXXXX")if 1/2 < x < 3/2 Answer link Related questions What are common mistakes students make when solving polynomial inequalities? How do I solve a polynomial inequality? How do I solve the polynomial inequality -2(m-3)<5(m+1)-12? How do I solve the polynomial inequality -6<=2(x-5)<7? How do I solve the polynomial inequality 1<2x+3<11? How do I solve the polynomial inequality -12<-2(x+1)<=18? How do you solve the inequality 6x^2-5x>6? How do you solve x^2 - 4x - 21<=0 A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)? How do you solve quadratic inequality, graph, and write in interval notation x^2 - 8x + 15 >0? How do you solve -x^2 - x + 6 < 0? See all questions in Polynomial Inequalities Impact of this question 1160 views around the world You can reuse this answer Creative Commons License