Question

What is the angular momentum of a rod with a mass of `8 kg` and length of `6 m` that is spinning around its center at `2 Hz`?

Answer 1

`"The angular momentum of rod is " 96pi`

Explanation:

`"The angular momentum of a rod spinning its center can be calculated using " L=I*omega`

`L:"represents angular momentum"`
`I:"represents moment of inertia"`
`omega:"represents angular velocity "`

`omega=2*pi*f" where f is frequency"`

`omega=2*pi*2=4pi`

`I=1/12*m*l^2(" moment of inertia for a rod spinning around its center")`

`m=8" kg ";l=6" m"`

`I=1/12*8*6^2=(8*36)/12=8*3=24`

`I=24*4pi=96 pi`