Question

The length of a rectangle is 5 cm more than twice its width. What is the largest possible width if the perimeter is at most 64 cm?

Answer 1

`width=9cm`

Explanation:

Perimeter of a rectangle`=2(a+b)` where `a` is the length and `b` is the width
As given we can write
`a=2b+5` by plugging this value

Perimeter of a rectangle`64=2(a+b)`
or
`a+b=64/2`
or
`a+b=32`
or
`2b+5+b=32`
or
`3b=32-5`
or
`3b=27`
or
`b=27/3`
or
`b=9`