The length of a rectangle is 5 cm more than twice its width. What is the largest possible width if the perimeter is at most 64 cm?

1 Answer
Aug 13, 2016

width=9cm

Explanation:

Perimeter of a rectangle=2(a+b) where a is the length and b is the width
As given we can write
a=2b+5 by plugging this value

Perimeter of a rectangle64=2(a+b)
or
a+b=64/2
or
a+b=32
or
2b+5+b=32
or
3b=32-5
or
3b=27
or
b=27/3
or
b=9