How do you simplify #sqrt2/(2sqrt3)#?

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Answer 1 · 2016-08-13T21:55:30

#1/(sqrt(6))#

Can write #2 = sqrt(2)sqrt(2)#

#(sqrt(2))/(sqrt(2)sqrt(2)sqrt(3)) = 1/(sqrt(2)sqrt(3)) = 1/(sqrt(6))#

Answer 2 · 2016-08-13T22:43:35

#sqrt6/6#

It is generally not good practice to leave a radical in the denominator so we try to change the denominator into a rational number.

This is called rationalising the denominator.

#sqrt2/(2sqrt3) xxsqrt3/sqrt3 " "sqrt3/sqrt3 = 1#

=#sqrt6/(2 xx 3)#

#sqrt6/6#