Question

Question #4c1cf

Answer 1

The pressure of the gas is 26 atm.

Explanation:

This looks like the time to apply the Ideal Gas Law:

`color(blue)(|bar(ul(PV = nRT)|)`,

where

• `P` is the pressure
• `V` is the volume
• `n` is the number of moles
• `R` is the gas constant
• `T` is the temperature

We can rearrange the Ideal Gas Law to get

`P = (nRT)/V`

`n = "4.95 mol"`
`R = "0.082 06 L·atm·K"^"-1""mol^"-1"`
`T = "(75 + 273.15) K = 348.15 K"`
`V = "5.4 L"`

`P = (nRT)/V = (4.95 color(red)(cancel(color(black)("mol"))) × "0.082 06" color(red)(cancel(color(black)("L")))"·atm·"color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 348.15 color(red)(cancel(color(black)("K"))))/(5.4 color(red)(cancel(color(black)("L")))) = "26 atm"`