How do you solve #8x^2 - 5x - 3 = 0# by completing the square?

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Answer 1 · 2016-08-16T12:49:35

#x=1, -3/8#

#8x^2-5x=3#

#x^2-5/8x=3/8#

#x^2-10/16x=3/8#

#x^2-10/16x+25/256=3/8+25/256#

#(x-5/16)^2=121/256#

#x-5/16=+-11/16#

#x=(+-11/16)+5/16#

#x=(5+-11)/16#

#x=1, -3/8#