How do you evaluate #log_81 9#?
1 Answer
Aug 16, 2016
Use the change of base formula to find:
#log_81 9 = 1/2#
Explanation:
The change of base formula tells us that for any
#log_a b = (log_c b) / (log_c a)#
So we find:
#log_81 9 = log_9 9 / log_9 81 = log_9 9 / log_9 9^2 = 1/2#