How do you find the derivative of # (2x-1)^3#?

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Answer 1 · 2016-08-17T17:32:40

#(dy)/dx = 6(2x-1)^2#

a simple technique to consider is using the chain rule
which states

#(dy)/dx = dy/(du)*(du)/dx#

here # y=(2x-1)^3 and u=2x-1 #

# (du)/dx = 2#

# (dy)/(du) = 3(u)^2#

now we can also just not replace the #u# so

# (dy)/(du) = 3(2x-1)^2#

now we can solve
#(dy)/dx = 6(2x-1)^2#