Question

Question #6ef73

Answer 1

`lim_(x->0)((2+x)^3-8)/x = 6`

Explanation:

`lim_(x->0)((2+x)^3-8)/x`

`=lim_(x->0)(x^3+6x^2+6x+8-8)/x`

`=lim_(x->0)(x(x^2+6x+6))/x`

`=lim_(x->0)x^2+6x+6`

`=0^2+6(0)+6`

`=6`