How do you find the derivative of #g(t) = 1/sqrt(t)#?
1 Answer
Aug 19, 2016
Explanation:
differentiate using the
#color(blue)"power rule"#
#g(t)=1/sqrtt=1/t^(1/2)=t^(-1/2)#
#rArrg'(t)=-1/2t^(-3/2)=(-1)/(2t^(3/2))=(-1)/(2sqrt(t^3)#
