What is the voltage of a galvanic cell made with zinc and aluminum at standard conditions?

1 Answer
Aug 22, 2016

ξcell=0.90V

Explanation:

The standard reduction potentials for zinc and aluminum are listed below:

Zn2++2eZn(s) ξ=0.76V

Al3++3eAl(s) ξ=1.66V

In a galvanic cell, the component with lower standard reduction potential gets oxidized and that it is added to the anode compartment. The second is therefore, forms the cathode compartment.

Since almuninum has the lowest standard reduction potential ξ=1.66V, therefore, it should be oxidized as follows:

Oxidation: Al(s)Al3++3e ξ=1.66V

Note that when the reduction equation is reversed, the sign of the standard reduction potential is reversed as well.

Since zinc will be in the cathode compartment, it will get reduced as follows:

Reduction: Zn2++2eZn(s) ξ=0.76V

The overall reaction in the galvanic cell is the sum of the two half equations; oxidation and reduction:

Oxidation: (Al(s)Al3++3e)×2 ξ=1.66V
Reduction: (Zn2++2eZn(s))×3 ξ=0.76V

RedOx: 2Al(s)+3Zn2+2Al3++3Zn(s) ξcell=0.90V

Therefore, the standard cell potential is : ξcell=0.90V

Note that the half equations where multiplied by the corresponding integers (2 and 3) in order to cancel the number of electrons from the overall equation.

Here is a video that further explains this topic:
Electrochemistry | The Standard Reduction Potential.