How do you solve #-4*6^(p+6)+4=2#?

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Answer 1 · 2016-08-22T12:28:19

#p = -6.387#

#-4*6^(p+6)+4 =2" isolate the term with the variable first"#

#(-4*6^(p+6))/-4=(-2)/-4#

#6^(p+6)=1/2 " variable is in the index" rArr log#

#log6^(p+6) = log (1/2)#

#(p+6) log6 = log(1/2)#

#p+6 = log(1/2)/log6 = -0.38685#

#p = -6.387#