How do you evaluate #log_64 (1/4)#?
1 Answer
Aug 23, 2016
Explanation:
Using the
#color(blue)"law of logarithms"#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(log_b a=nhArra=b^n)color(white)(a/a)|)))#
#rArrlog_(64)(1/4)=nrArr1/4=64^nrArrn=-1/3# Note
#64^(-1/3)=1/(64^(1/3))=1/4#
