How do you solve the following system?: #-2x+12y=-20 , y=1/3x #

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Answer 1 · 2016-08-23T10:43:13

#x=-10#

#y=-10/3#

#-2x+12y=-20#

or

#2x-12y=20#

or

#x-6y=10#

#y=x/3#

or

#x=3y#

Plugging the value #x=3y# in the equation #x-6y=10#

We get

#3y-6y=10#

or

#-3y=10#

or

#y=-10/3#--------------------------Ans #1#

Plugging the value
#y=-10/3# in the equation #x=3y# we get

#x=3times(-10/3)#

or

#x=-10#-----------------------------Ans #2#