How do you solve the system of linear equations #2x − 4y = 6# and #3x − y = 12#?
1 Answer
Aug 25, 2016
#x=4.2#
#y=0.6#
Explanation:
Given -
#2x-4y=6# ---------------(1)
#3x-y=12# ----------------(2)
#-y=12-3x#
#y=-12+3x#
Substitute
#2x-4(-12+3x)=6#
#2x+48-12x=6#
#-10x+48=6#
#-10x=6-48=-42#
#x=(-42)/(-10)=4.2#
Substitute
#3(4.2)-y=12#
#12.6-y=12#
#-y=12-12.6=-0.6#
#y=0.6#