Question

How do you solve the quadratic `3p^2-4=-6` using any method?

Answer 1

`p=+-isqrt(2/3)`.

Explanation:

Add `4` to both sides to get `3p^2=-2`.

Divide both sides by `3` to get `p^2=-2/3`.

Square root both sides to get `p=+-sqrt(-2/3)`, which is equivalent to `p=+-isqrt(2/3)`.