How do you write the vector equation that passes through point (-6,10) and parallel to <3,2>?

Question

4294 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-26T11:38:09

#r = < x, y > =<3t-6, 2t+10>#

If a vector #V# is parallel to the vector #U#, then #V=t U#, where t is

a scalar.l

Let #r = < x, y ># be the position vector #OP# to the point P(x, y) on

the line through A(-6, 10) in the direction of #<3, 2>#. Then,

Vector #AP#

#= OP - OA#

# = < x+6, y-10 >#

# = t <3, 2 >#, .

So, # r = < x, y > = < 3t-6, 2t+10 >#