Question

Question #6fc66

Answer 1

One cyclist traveling towards North-West and another towards South.So angle between them is `theta=(45+90)^@=135^@`

Let the starting point of journey of two cyclists be O. After t hr first cyclist reaches at A traveling @ 22km/hr and at the same time the second cyclist reaches at B traveling @ 14km/hr .

`"So in "DeltaAOB`

`/_ AOB=theta=135^@`

`OA=22t" km"`

`OB=14t" km"`

`AB=80" km"`

Applying triangle law

`AB^2=OA^2+OB^2-2OA*OBcostheta`

`=>80^2=(22t)^2+(14t)^2-2*22t*14tcos135^@`

`=>t^2(484+196+616*cos45^@)=6400`

`=>t^2(484+196+616*1/sqrt2)=6400`

`=>1115.58t^2=6400`

`=>t^2=6400/1115.58`

`=>t=sqrt(6400/1115.58)~~2.39hr`