How do you graph #-5x+2y=10# using intercepts?

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Answer 1 · 2016-08-26T22:22:08

The intercepts are #(-2, 0) and (0, 5)#

All points along the #x-#axis have their y- value =0.

All points along the #y-#axis have their x- value =0.

To find the #y#intercept of a line,make x = 0.

To find the #x#intercept of a line,make y = 0.

Once you have the #x- and y-# intercepts, you have two points of the line.

Draw a line which passes through the two points.

#-5color(red)(x) +2color(blue)(y) = 10#

For #x-#int, #color(blue)(y=0)#

#rarr -5x +2color(blue)((0)) = 10#

#-5x = 10" div -5#

#x = 10/(-5) = -2 " "x = -2 #

For #y-#int, #color(red)(x=0)#

#rarr -5color(red)((0))x +2y = 10#

#2y= 10" "div 2#

#y = 10/(2) = 5 " "y = 5#