Question

What is the pOH of a `8.4x10^-11 M` `OH^-` solution?

Answer 1

`pOH=10.08`

Explanation:

The `pOH` of a solution is defined in terms of the concentration of hydroxide ions in solution as follows:

`pOH=-log[OH^(-)]`.

In this question, `[OH^(-)]=8.4xx10^(-11)M`, thus the `pOH` can be calculated by:

`pOH=-log(8.4xx10^(-11))=10.0757~=10.08`

Note that if the concentration is given with 2 significant figures , the `pOH` value is written with two decimal places.