Question

How do you divide `(x^4-2x^3-2x^2+5x+3)/(x^2-3)`?

Answer 1

`(x^4-2x^3-2x^2+5x+3)/(x^2-3) = x^2-2x+1-(x+6)/(x^2-3)`

Explanation:

One way is to long divide the coefficients, not forgetting to include a `0` for the coefficient of the missing `x` term in the divisor...

We find:

`(x^4-2x^3-2x^2+5x+3)/(x^2-3) = x^2-2x+1-(x+6)/(x^2-3)`