How do you evaluate log_15 1log151?

2 Answers
Aug 31, 2016

Zero

Explanation:

2^3=823=8 which can also be written as log_2(8)=3log2(8)=3

This is I think quite easy to remember

So given log_15(1)=xlog15(1)=x where you want to find X
Rewrite as 15^x=115x=1

Any number to the power of zero =1

So X=1

Aug 31, 2016

log_15 1 = 0log151=0

Explanation:

The question we need to ask with log format is..

"What index/power of 15 will give 1?"

Any base raised to the power of 0 will give 1.

15^0 = 1150=1

Log form and index form are interchangeable.

log_15 1 = 0 hArr 15^0 = 1log151=0150=1

Remember that 0^0 00 is undefined., so log 0log0 is undefined.