How do you simplify #6 sqrt5 - 2sqrt5#?

2 Answers
Aug 31, 2016

It's pretty simple, actually: #6sqrt5- 2sqrt5=4sqrt5#

Explanation:

What we can do, is we can create a variable for the #sqrt5# and then substitute back after we do the math.

Let's say #x# can be equal to #sqrt5#. So then our simplified question would read: #6x-2x# when we place #x# in for the #sqrt5#.

#6x-2x=4x# so then we just take the #sqrt5# and place it back in for the #x# and we get #4sqrt5#.

Aug 31, 2016

4#sqrt#5

Explanation:

#sqrt#5(6-2) = 4#sqrt#5