How do you solve #2/(x+3)<0#? Precalculus Solving Rational Inequalities Solving Rational Inequalities on a Graphing Calculator 1 Answer Shwetank Mauria Sep 1, 2016 #x<-3# Explanation: As #2/(x+3)<0#, this means #2/(x+3)# is negative. As #2# is positive, it is possible only if #x+3# is negative i.e. #x+3<0# or #x<-3# Answer link Related questions How do I solve the rational inequality #(x-4)/(x+5)<4# using a TI-84? How do I solve the rational inequality #(x+10)/(3x-2)<=3# using a TI-84? How do I solve the rational inequality #(x+2)/(2x+1)>5# using a TI-84? How do I solve the rational inequality #(3x-2)/(x+2)<=1/3# using a TI-83? How do I solve the rational inequality #(x^2-1)/(x+1)<2# using a TI-83? How do I solve the rational inequality #(x^2-x-6)/(x+2)<=-3# using a TI-83? How do you solve rational inequalities? How do you solve the inequality #(x^2-2x-24)/(x^2-8x-20)>=0#? How do you solve the inequality #x^3-x^2-6x>0#? How do you solve #(16-x^2)/(x^2-9)>=0#? See all questions in Solving Rational Inequalities on a Graphing Calculator Impact of this question 2947 views around the world You can reuse this answer Creative Commons License