Question #706f8
1 Answer
It accelerates well.
Explanation:
In simple terms, acceleration,
#color(purple)(bar(ul(|color(white)(a/a)color(black)(a = (Deltav)/(Deltat)color(white)(a/a)|)))#
Here
The problem tells you that a car goes from
#Deltav = "60 mi/h" - "0 mi/h" = "60 mi/h"#
You also know that it takes
#Deltat = "6 s" - "0 s" = "6 s"#
Since you know the values of
To calculate it, you must convert the change in velocity to meters per second by using a series of conversion factors
#60 color(red)(cancel(color(black)("mi")))/(1color(red)(cancel(color(black)("h")))) * (1.61 color(red)(cancel(color(black)("km"))))/(1color(red)(cancel(color(black)("mi")))) * (10^3"m")/(1color(red)(cancel(color(black)("km")))) * (1color(red)(cancel(color(black)("h"))))/(60color(red)(cancel(color(black)("min")))) * (1color(red)(cancel(color(black)("min"))))/"60 s" = "26.83 m s"^(-1)#
You will have
#a = ("26.83 m s"^(-1))/"6 s" ~~ "4.5 m s"^(-2)#
What this tells you is that with every passing second, the velocity of the car increases by approximately
Therefore, because you know the change in velocity and the time needed for that change to take place, you can say that the car accelerates well.
It can be argued that you can also say that the car is fast, but for that to make a valid statement you'd need to know its top speed. In relative terms, a car that accelerates that well will most likely be very fast, but I don't think that this is the conclusion you must draw here.