How do you simplify #(sec^2x) - (tan^2x)#?
1 Answer
Sep 3, 2016
Explanation:
Note that:
#sin^2 x + cos^2 x = 1#
Hence:
#cos^2 x = 1 - sin^2 x#
and we find:
#sec^2 x - tan^2 x = 1/cos^2 x - sin^2 x/cos^2 x#
#color(white)(sec^2 x - tan^2 x) = (1 - sin^2 x)/cos^2 x#
#color(white)(sec^2 x - tan^2 x) = cos^2 x/cos^2 x#
#color(white)(sec^2 x - tan^2 x) = 1#