How do you solve #sqrt(x-3) =1# and find any extraneous solutions?

1 Answer
Jim G.
Sep 3, 2016

#x=4#

Explanation:

The first step is to #color(blue)"square both sides"#

#rArr(sqrt(x-3))^2=1^2#

#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(sqrtaxxsqrta=(sqrta)^2=a)color(white)(a/a)|)))#

#rArrx-3=1rArrx=1+3=4#

There are no extraneous solutions.

Related questions
See all questions in Radical Equations
Impact of this question
1041 views around the world
You can reuse this answer
Creative Commons License