Which of the following is the vertex of the quadratic equation $y = 6x^2 – 24x + 32$ ?

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Answer 1 · 2016-09-04T13:45:35

Vertex $->(x,y)=(2,8)$

The method used is part way to completing the square plus anticipating part of the final stage.

Write as: $" "y=6(x^2-24/6x)+32$

$x_("vertex")=(-1/2)xx(-24/6) = 2$
Thus by substitution we have:

$y_("vertex")=6(2)^2-24(2)+32$

$y_("vertex")=8$

Which of the following is the vertex of the quadratic equation y = 6x^2 – 24x + 32y = 6x^2 – 24x + 32?