Question

How would you calculate the value of `K_p` for the equation `C(s) + CO_2(g) leftrightarrow 2CO(g)`?

Answer 1

For `C(s) + CO_2(g) rightleftharpoons 2CO`;

`K_p=p_"carbon monoxide"^2/(p_"carbon dioxide")`

Explanation:

And thus `K_p` is simply the quotient of the partial pressures, modified by their stoichiometric coefficient. Carbon does not appear in the expression as a solid does not exert a partial pressure, nor does it express a concentration in `K_c`.