How do you simplify #3/(cosy-siny)-2/(sin^2y-cos^2y)#?

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Answer 1 · 2016-09-05T15:20:34

#=>(-3siny - 3cosy - 2)/((siny + cosy)(siny - cosy)#

#=>3/(cosy - siny) - 2/((siny + cosy)(siny - cosy))#

#=>-3/(siny - cosy) - 2/((siny + cosy)(siny - cosy))#

Put on a common denominator:

#=>-(3(siny + cosy))/((siny - cosy)(siny + cosy)) - 2/((siny + cosy)(siny - cosy))#

#=>(-3siny - 3cosy - 2)/((siny + cosy)(siny - cosy)#

As far as I can see, you can't simplify further.

Hopefully this helps!