Light is travelling at a speed of #2.29*10^8# #m#/#s# through ice. What is the index of refraction of ice?

1 Answer
Sep 6, 2016

#1.31#

Explanation:

We know that
Refractive index of a medium #n# #=("Velocity of light in Vacuum "c)/("Velocity of light in medium")#
Inserting given value and taking #c=3xx10^8ms^-1#, we get

Refractive index of ice #n=(3xx10^8)/(2.29xx10^8)#

#=>n=1.31#