How do you solve #2secxtanx+2secx+tanx+1=0# in the interval [0,360]?

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Answer 1 · 2016-09-08T13:38:17

The solution set is #{(3pi)/4, (7pi)/4}#.

Factor:

#2secx(tanx + 1) + 1(tanx + 1) = 0#

#(2secx + 1)(tanx + 1)= 0#

#secx = -1/2 and tanx = -1#

#cosx = -2 and tanx = -1#

#x = O/ and x = (3pi)/4 and (7pi)/4#

Hence, the solution set is #{(3pi)/4, (7pi)/4}#.

Hopefully this helps!