How do you solve #-2( x - 5) = 2x - 30#?

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Answer 1 · 2016-09-08T21:43:00

#x=10#

Distribute #-2# across the bracket with #(x -5)# to give

# -2x+10= 2x-30#

Add 30 on both sides to get

#-2x+40=2x#

Add #2x# on both sides to cancel out the #-2x# to get

#40=4x#

divide by 4 on both sides

#10=x#

TO CHECK ANSWER:

Plug in 10 for #x# on both sides.

#−2(x−5)=2x−30#

#−2(10−5)=2(10)−30#

#-20+10=20 -30#

#-10 =-10#