How do you solve #sqrt(4x+2)-5=0#?

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Answer 1 · 2016-09-09T10:13:47

The answer is #x=23/4#.

Add #5# to both sides of the equation.

#sqrt(4x+2)=5#

Square both sides.

#(sqrt(4x+2))^2=5^2#

Simplify.

#4x+2=25#

Subtract #2# from both sides.

#4x=25-2#

Simplify.

#4x=23#

Divide both sides by #4#.

#x=23/4#