How do you solve #5(6-4x)=25#?

2 Answers
Sep 10, 2016

#x=1/4#

Explanation:

Let's start!
#5(6-4x) = 25#

We can't do anything with that 5 outside of the parenthesis, so we divide both sides by 5.
#(5(6-4x))/5 = 25/5#

#6-4x = 5#

Now we want all of the constants on one side, and all of the variables on the other. So, we add #4x# to both sides,
#6 - 4x + 4x = 5 + 4x#
#6 = 5 + 4x#
and subtract #5# from both sides.
#6 - 5 = 5 +4x - 5#
#1 = 4x#

Finally, we can divide both sides by 4 to get rid of #x#'s coefficient.
#1/4 = (4x)/4#
#1/4 = x#
#x = 1/4 square#

Sep 10, 2016

#x=1/4#

Explanation:

#5(6-4x)=25#
#30-20x=25#
#20x=30-25#
#20x=5#
#x=5/20=1/4#