Question

How do you solve `x^2+10x-31=0` by completing the square?

Answer 1

`x= -5+ 2sqrt14 or x= -5-2sqrt14`

Explanation:

`x^2+10x-31=0 or (x+5)^2 -25-31=0 or (x+5)^2-56=0 or (x+5)^2 =56 or (x+5)= +-sqrt56 or x+5= +- 2sqrt14 or x= -5+- 2sqrt14 :. x= -5+ 2sqrt14 or x= -5-2sqrt14`[Ans]