How do you solve #8- ( x + 3) = 4#?

1 Answer
Jim G.
Sep 10, 2016

#x=1#

Explanation:

distribute the bracket.

#rArr8-x-3=4rArr5-x=4#

subtract 5 from both sides of the equation.

#cancel(5)-xcancel(-5)=4-5rArr-x=-1#

To solve for x divide both sides by - 1.

#rArr(cancel(-1) x)/cancel(-1)=cancel(-1)^1/cancel(-1)^1#

#rArrx=1" is the solution"#

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