What is the value of #(8a^6b^12)/(4a^3b^4)#?

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Answer 1 · 2016-09-11T10:19:09

Simplify the numbers (cancel)
Subtract the indices of like bases.

#(cancel8^2a^6b^12)/(cancel4a^3b^4)#

=#2a^3b^8#

Answer 2 · 2016-09-11T10:24:39

#2 a^(3) b^(8)#

We have: #(8 a^(6) b^(12)) / (4 a^(3) b^(4))#

#= (2 a^(6) b^(12)) / (a^(3) b^(4))#

Using the laws of exponents:

#= 2 (a^(6 - 3)) (b^(12 - 4))#

#= 2 a^(3) b^(8)#