How do you find the slope and intercept of #8x-1/2y=-2#?

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Answer 1 · 2016-09-11T16:17:21

#8x-1/2y=-2#

Solve for y

#-1/2y=-8x-2#

#y=16x+4#

Slope-intercept form: #y=mx+b#, m=slope, b=y-intercept

Slope=16, y-intercept=#(0,4)#

x-intercept: let y=0

#0=16x+4#

#-4=16x#

#-1/4=x#

x-intercept= #(-1/4,0)#