How do you divide #(x-4)/(2x^2)-:(2x+3)/(x+4)#?

1 Answer
Sep 12, 2016

#((x-4)(x+4))/(2x^2(2x+3)#

Explanation:

Treat algebraic fractions the same as arithmetic ones!

#(x-4)/(2x^2)color(red)(-:(2x+3)/(x+4))#

#(x-4)/(2x^2)color(red)(xx(x+4)/(2x+3))#

#((x-4)(x+4))/(2x^2(2x+3)#

This does not simplify further and It is probably better left in factor form, rather than as

#(x^2-16)/(4x^3+6x^2#