Question

How do you solve `g( h + {2}/{3} ) = 1` for `h`?

Answer 1

`h=(3-2g)/(3g)`

Explanation:

`g(h+2/3)=1`

`h+2/3 = 1/g`

`h= 1/g-2/3`

`h=(3-2g)/(3g)`