How do you find the remainder for $(x^3+11x^2+24x+9)div(x+2)$ ?

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Answer 1 · 2016-09-13T04:18:00

$" The Remainder"=-3$ .

We will use the Remainder Theorem :

$"A poly. "P(x)," when divided by "(px+q)" leaves remainder "P(-q/p)$ .

Let $P(x)=x^3+11x^2+24x+9$ .

Comparing $(x+2)$ with $(px+q), p=1, q=2$ .

Hence by the Remainder Theorem,

The Remainder $=P(-q/p)=P(-2)$

$=(-2)^3+11(-2)^2+24(-2)+9$

$=-8+44-48+9$ .

$:." The Remainder"=-3$ .

Enjoy Maths.!

How do you find the remainder for (x^3+11x^2+24x+9)div(x+2)(x^3+11x^2+24x+9)div(x+2)?