Question

What is `f(-2)` if `f(x)=4x^2-x-23`?

Answer 1

`f(-2)=-5`

Explanation:

As `f(x)=4x^2-x-23`, we can find `f(-2)`, by putting `x=-2` in the function.

Hence `f(-2)=4×(-2)^2-(-2)-23`

= `4×4+2-23`

= `16+2-23`

= `-5`