Question

A charge of `45 C` passes through a circuit every `6 s`. If the circuit can generate `98 W` of power, what is the circuit's resistance?

Answer 1

The resistance is 1.742 `Omega`

Explanation:

The current in the circuit is the amount of charge that passes by a point per second. It is found from the equation `I = (Delta Q)/(Delta t)= (45 C)/(6 s) = 7.5 A`.

The power in a circuit is found from the equation `P = IV = I^2R`. This means that the resistance is `R = (P)/(I^2) = (98 W)/(7.5 A)^2 = 1.742 Omega`