Question

What is the heat released when 25.0 grams of water freezes at 0°C?

Answer 1

To calculate the amount of heat entering or leaving a system, the equation `Q=mcΔT` is used.

Explanation:

m = mass (in grams)
c = specific heat capacity (J/g°C)
ΔT = change in temperature (°C)

Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.

The mass given is 25.0 grams.

As for the change in temperature, I will assume that it start off at room temperature, 25°C.

`25°C - 0°C = 25°C`

`Q=mcΔT`

`Q = 25 grams * 4.19 J/(g°C) * 25°C`

`Q = 2618.75 J`

Take into account significant figures and the answer should be

`2.6 * 10^3 J`